The Mathematics of Maybe: Introduction to Probability
7.1 What is Probability?
Probability is a special kind of measurement. While a ruler measures length and a weighing scale measures mass, probability measures how likely an event is to happen. It helps us turn uncertainty into a number we can understand.
Think about these questions:
- Will it rain this evening?
- Will our school team win the hockey match?
- Who will be picked in the lucky draw?
These are random events. We know what could happen, but we cannot be 100 % sure what will happen. When you say, "It is unlikely to rain because the sun is shining," you are giving a personal or subjective probability based on what you see. In this chapter, we learn how to measure chance more objectively.
7.1.1 What is Randomness?
Randomness means an action or situation where the exact result cannot be predicted, even though we know all the possible results.
- Tossing a coin: The result is either Heads or Tails, but you cannot know which one will appear on a single toss.
- Rolling a die: The top face can show 1, 2, 3, 4, 5, or 6. You cannot say which number will appear before you roll.
An experiment that can be repeated and gives unpredictable results each time is called a random experiment or trial. In a lucky draw, every student has an equal chance of being chosen, but no one knows who will be picked in advance.
Tossing a coin to decide which cricket team bats first is considered fair because both outcomes are equally likely. Randomness helps us create fairness.
7.1.2 The Probability Scale
Probability is measured on a scale from 0 to 1.
- 0 means the event is impossible.
- 1 means the event is certain.
- 0.5 means there is an even chance — the event is just as likely to happen as not.
If your school has a 0.75 probability of winning a match, it means there is a 75 % chance of victory. Most real-life probabilities fall somewhere between 0 and 1.
<| Event | What it means on the scale |
|---|---|
| Getting a number greater than 6 on a die | Impossible — a standard die only has numbers 1 to 6. |
| Rolling a 3 on a standard die | Less likely — only one face shows 3 out of six. |
| Flipping a fair coin and getting heads | Even chance — heads and tails are equally likely. |
| Drawing a number card (2 to 10) from a 52-card deck | More likely — 36 out of 52 cards fit this. |
| Choosing a red sweet from a bag of only red sweets | Certain — every sweet is red. |
7.2 Measuring Probability Objectively
Instead of guessing, we can use two objective methods:
<- Experimental probability: Collect data by performing an experiment many times or looking at past records. We calculate the relative frequency of the event.
- Theoretical probability: Use reasoning. We assume every outcome is equally likely in a fair situation and count favorable outcomes.
7.2.1 Experimental Probability
In an experiment, each result is called an outcome. The list of every possible outcome is called the sample space.
- Coin toss sample space: S = {H, T}
- Die roll sample space: S = {1, 2, 3, 4, 5, 6}
If you roll a die 50 times and a 4 appears 8 times, the experimental probability is 850 = 0.16. This value is also called the relative frequency.
<<7.2.2 Theoretical Probability
Theoretical probability tells us what we expect in a perfectly fair world. It does not need an experiment.
For a fair six-sided die:
- P(rolling a 4) = 16 ≈ 0.167
- P(rolling an even number) = 36 = 12
The game Snakes and Ladders comes from ancient India. It evolved from a dice game called Jñān-Chaupad, which taught moral lessons. Each ladder stood for a virtue and each snake stood for a vice.
7.2.3 Analysing Statistical Data Using Probability
Businesses and scientists use collected data to estimate probabilities. If a class survey shows 20 out of 50 students prefer mango, the probability that a randomly chosen student from that class likes mango is:
To guess the needs of a whole school of 1,500 students, we apply the same rate: about 40 % of 1,500 = 600 mangoes. Using a larger and more representative sample makes the estimate more trustworthy. This process is called sampling.
Even in a fair game, experimental results may differ from theoretical results when the number of trials is small. As you increase the number of trials, the experimental probability gets closer to the theoretical probability. This is known as the Law of Large Numbers.
Gambler's Fallacy
Some people think that if a coin lands on heads many times in a row, tails becomes "due." This is a mistake. A coin has no memory. Every flip is a fresh start. The probability of tails on the next flip is still 12.
Believing that past random events change the odds of future independent events is called the Gambler's Fallacy. In Snakes and Ladders, each die roll is independent. Three sixes in a row do not make a fourth six less likely.
Fair and Unbiased
A coin is called fair or unbiased when it is perfectly balanced, so neither side is favored. A random toss means the coin is thrown freely without cheating or interference.
Exercise Set 7.2
1. A teacher picks a sample of 30 sweets: 10 red, 8 green, 7 yellow, 5 blue.
(i) P(green) = 830 = 415 ≈ 0.267.
(ii) Yellow proportion in the sample = 730. Estimated yellow sweets in 600 = 600 × 730 = 140 sweets.
2. A sample of 40 students: 14 Science, 11 Arts, 9 Sports, 6 Debate. Whole school = 800.
(i) P(Arts) = 1140 = 0.275.
(ii) Sports proportion = 940. Estimated in 800 = 800 × 940 = 180 students.
3. Toss a coin 20 times.
(i) & (ii) These depend on your actual experiment. Record your own counts.
(iii) Experimental P(heads) = Your heads count20.<
(iv) For a fair coin, the probability of tails on the next toss is still 12, no matter what happened before.
4. Toss a paper cup 100 times.
Record how many times it lands on its bottom, top, and side. The experimental probability for each position is count100. For example, if it lands on its side 40 times, P(side) = 0.4.
5. What is the probability of getting an even number on a fair die?
Even numbers are {2, 4, 6}. P = 36 = 12 = 0.5.
6. A die is rolled 12 times and shows '3' three times.
(i) Experimental P(3) = 312 = 14 = 0.25.
(ii) Theoretical P(3) = 16 ≈ 0.167.
(iii) They differ because 12 trials is a small number. If you roll 60, 600, or 6,000 times, the experimental probability will move closer and closer to 16 (Law of Large Numbers).
7.3 Elements of Probability
7.3.1 Sample Space
The sample space, written as S, is the complete set of all possible outcomes of a random experiment. The number of elements inside it is called the sample size, written as n(S).
Rules for writing a sample space:
- Every possible outcome must be listed.
- Do not repeat the same outcome.
- n(S) is the total count of unique outcomes.
| Experiment | Sample Space (S) | Sample Size n(S) |
|---|---|---|
| Rain tomorrow (yes / no) | {Rain, No Rain} | 2 |
| Match result | {Win, Lose, Draw} | 3 |
| Tossing one coin | {H, T} | 2 |
| Rolling one die | {1, 2, 3, 4, 5, 6} | 6 |
| Tossing two coins | {HH, HT, TH, TT} | 4 |
If a question needs more detail, expand the sample space. For example, instead of just {Rain, No Rain}, you could use {No Rain, Drizzle, Light Rain, Heavy Rain} to match the level of detail required.
7.3.2 Events
An event is any single result or group of results we are interested in. It is a smaller set picked from the sample space.
- Two coins: Event "at least one head" = {HH, HT, TH}
- One die: Event "number greater than 4" = {5, 6}
- Fruit basket {Apple, Banana, Orange}: Event "yellow fruit" = {Banana}
Exercise Set 7.3
1. When a single 6-sided die is rolled, what is the total number of possible outcomes in the sample space?
n(S) = 6.
2. Write the sample space S for the following:
(i) Rolling a die and tossing a coin together:
S = {1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, 6T}. n(S) = 12.
(ii) Choosing a random integer between –5 and +5:
S = {–5, –4, –3, –2, –1, 0, 1, 2, 3, 4, 5}. n(S) = 11.
(iii) A box with 5 green and 7 red balls; one ball is drawn:
By colour: S = {Green, Red}. n(S) = 2.
(If each ball is different: S = {G1, G2, G3, G4, G5, R1, R2, R3, R4, R5, R6, R7}. n(S) = 12.)
3. Snacks: Samosa, Pakora, Bhaji. Drinks: Chai, Lassi.
(i) S = {(Samosa, Chai), (Samosa, Lassi), (Pakora, Chai), (Pakora, Lassi), (Bhaji, Chai), (Bhaji, Lassi)}.
(ii) Event "Selecting Samosa" = {(Samosa, Chai), (Samosa, Lassi)}.
7.4 Tree Diagrams
A tree diagram is a picture that helps us list every possible result of a multi-step experiment. Each branch shows one possible outcome, and new branches grow from it for the next step.
Every complete path from the start to the tip of a branch is one full outcome. Tree diagrams also let us write probabilities on each branch.
<For the experiment above, the sample space is S = {HH, HT, TH, TT}.
The probability of getting two heads (HH) is:
Exercise Set 7.4
1. Basket A: 1 Apple, 2 Oranges. Basket B: 1 Banana, 1 Mango. One fruit is picked from each.
(i) Tree diagram: From A, branches to Apple (1/3), Orange1 (1/3), Orange2 (1/3). From each, branches to Banana (1/2) and Mango (1/2).<
(ii) Sample space: {(Apple, Banana), (Apple, Mango), (Orange, Banana), (Orange, Mango)}. If oranges are treated as distinct items, there are 6 outcomes.
(iii) P(Apple and Banana) = 13 × 12 = 16.
2. A box contains 3 red, 4 black, and 2 green pens. You pick one, put it back, then your friend picks one.
(i) Possible colour outcomes: Red, Black, Green. Tree diagram: First pick branches R (3/9), B (4/9), G (2/9). From each, second pick branches R, B, G with the same probabilities.
(ii) P(same colour) = P(RR) + P(BB) + P(GG)
= 39·<39 + 49·<49 + 29·<29
= 981 + 1681 + 481 = 2981 ≈ 0.358.
End-of-Chapter Exercises
1. Fill in the blanks.
(i) The probability of an impossible event is 0.<
(ii) The set of all possible outcomes of a random experiment is called the sample space.<
(iii) The probability of an event that is certain to happen is 1.<
(iv) Tossing a fair coin has a probability of 12 for getting heads.
2. In a survey of 50 students, 15 said they liked football. The number of students who like football is 15, and the relative frequency is 1550 = 0.3.
3. Which experiments have equally likely outcomes? Explain.
(i) A driver starts a car — No. Mechanical condition and battery life can make one outcome more likely.
(ii) Tossing a fair coin — Yes. The coin is balanced, so heads and tails have the same chance.
(iii) Rolling a fair 6-sided die — Yes. Each face has the same shape and weight.
(iv) Choosing a marble from a bag with 3 red and 7 blue — No. There are more blue marbles, so blue is more likely.
(v) A baby is born, boy or girl — In theory, yes — there are two outcomes and we usually treat them as equally likely for simple models, though real-world data shows a slight difference.
4. Write the sample space and calculate the probability.
(i) Two coins tossed. S = {HH, HT, TH, TT}. P(at least one head) = 34.<
(ii) Ten cards numbered 1 to 10. Even numbers = {2, 4, 6, 8, 10}. P(even) = 510 = 12.<
(iii) A die rolled once. Numbers > 4 are {5, 6}. P = 26 = 13.<
(iv) Bag with 3 red, 2 blue, 1 green. Not red means blue or green (3 balls). P(not red) = 36 = 12.<
(v) Three coins tossed. S has 8 outcomes. Exactly two heads = {HHT, HTH, THH}. P = 38.
5. A bag has 3 candies: strawberry, lemon, and mint. One is picked at random. What is the probability of picking a strawberry candy?
P(Strawberry) = 13.
6. A child has 2 shirts (red, blue) and 3 pants (jeans, khakis, shorts). List all possible outfits in a table.
| Shirt | Pants | Outfit |
|---|---|---|
| Red | Jeans | Red + Jeans |
| Red | Khakis | Red + Khakis |
| Red | Shorts | Red + Shorts |
| Blue | Jeans | Blue + Jeans |
| Blue | Khakis | Blue + Khakis |
| Blue | Shorts | Blue + Shorts |
Total outfits = 2 × 3 = 6 combinations.
7. Tyre replacement distances for 1,000 cases.
| Distance (km) | Less than 4000 | 4001 to 9000 | 9001 to 14000 | More than 14000 |
|---|---|---|---|---|
| Number of cases | 20 | 210 | 325 | 445 |
(i) P(less than 4000 km) = 201000 = 0.02.
(ii) P(between 4000 and 14000 km) = 210 + 3251000 = 5351000 = 0.535.
(iii) P(more than 14000 km) = 4451000 = 0.445.
8. The letters of the word PEACE are placed on cards. Leela draws one card without looking.
Letters: P, E, A, C, E. Total = 5 cards.
(i) P(P, E, or C) = 1 + 2 + 15 = 45 = 0.8.
(ii) P(not an E) = 35 = 0.6. (The non-E cards are P, A, C.)
9. A game of chance uses a spinner with numbers 1 to 8 as equally likely outcomes.
<(i) P(8) = 18.<
(ii) Odd numbers are {1, 3, 5, 7}. P(odd) = 48 = 12.<
(iii) Numbers > 2 are {3, 4, 5, 6, 7, 8}. P = 68 = 34.<
(iv) Numbers < 9 are {1, 2, 3, 4, 5, 6, 7, 8}. P = 88 = 1 (certain).<
(v) Multiples of 3 are {3, 6}. P = 28 = 14.
10. A basket has 4 red balls and 5 blue balls. One ball is drawn and laid aside, then a second is drawn.
Total = 9 balls. Tree diagram branches:
First draw: Red (49) → Second: Red (38) or Blue (58).<
First draw: Blue (59) → Second: Red (48) or Blue (48).<
(i) P(Red then Blue) = 49 × 58 = 2072 = 518.<
(ii) P(2 Blue balls) = 59 × 48 = 2072 = 518.
11. I throw a pair of 6-sided dice. Write an event with probability 0 and an outcome with probability 1.
Event with probability 0: "The sum of the two dice is 1" (the lowest sum is 2).<
Outcome with probability 1: "The sum is a number from 2 to 12" (every possible throw gives a sum in this range).
12. Calculate the probabilities.
(i) Two dice rolled. Prime sums greater than 5 are 7 and 11.
Ways to get 7: 6 ways. Ways to get 11: 2 ways. Total favourable = 8. Total outcomes = 36.
P = 836 = 29.<
(ii) Bag: 4 red, 3 green, 2 blue. Two balls drawn without replacement.
P(both different colours) = 1 – P(both same).<
P(RR) = 49·<38 = 1272. P(GG) = 39·<28 = 672. P(BB) = 29·<18 = 272.<
P(same) = 2072 = 518. Therefore P(different) = 1 – 518 = 1318.<
(iii) Three coins tossed. First coin shows heads and exactly two heads in total.
Fix first as H. We need exactly one more H in the next two tosses: {HHT, HTH}.<
P = 28 = 14.<
(iv) Four-digit number from 1, 2, 3, 4 with no repetition. Total numbers = 4! = 24.
For the number to be even, the last digit must be 2 or 4.
If last is 2: arrange 1, 3, 4 in front → 6 ways.
If last is 4: arrange 1, 2, 3 in front → 6 ways.
Favourable = 12. P = 1224 = 12.<
(v) 3 multiple-choice questions, 4 options each, guessing exactly 2 correct.
Choose which 2 are correct: C(3,2) = 3 ways.
P = 3 × (14)² × (34) = 3 × 116 × 34 = 964 ≈ 0.141.
13. A box contains 4 balls numbered 1 to 4.
(i) With replacement tree: Each first branch (1,2,3,4) leads to second branches (1,2,3,4). Sample space size = 4 × 4 = 16.<
(ii) Without replacement tree: Each first branch leads to three remaining numbers. Sample space size = 4 × 3 = 12.<
(iii) Sizes are 16 and 12 respectively.
14. List the sample space for tossing a coin and drawing a card from 6 cards numbered 1 through 6.
S = {H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}. n(S) = 12.
15. Three coins are tossed and the number of heads is recorded. Which list is a valid sample space?
The correct list is {0, 1, 2, 3} (option iv).<
(i) {1,2,3} fails because 0 heads is possible (TTT).<
(ii) {0,1,2} fails because 3 heads is possible (HHH).<
(iii) {0,1,2,3,4} fails because 4 heads is impossible with only 3 coins.
16. A dye is dropped at random on a 3 m × 2 m rectangular region. What is the probability it lands inside a circle of diameter 1 m?
<Area of rectangle = 3 × 2 = 6 m².
Radius of circle = 0.5 m. Area of circle = π × (0.5)² = π4 m².
P = π/46 = π24.
